At a local college, 102 of the male students are smokers and 408 are non-smokers. Of the female students, 240 are smokers and 360 are non-smokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are non-smokers? Do not round your answer.

Answer: Probability that both are non smokers is 0.48.Step-by-step explanation:Since we have given that Number of male smokers = 102Number of male non smokers = 408Total male = 102+408=510Number of female smokers = 240Number of female non smokers = 360Total female = 240+360 = 600According to question,A male student and a female student from the college are randomly selected for a survey,So, Probability that both are non smokers is given byP(both are smokers ) = P(Male smoker) × P(female smoker)[tex]P(both)=\dfrac{360}{600}\times \dfrac{408}{510}\\\\P(both)=\dfrac{146880}{306000}\\\\P(both)=0.48[/tex]Hence, probability that both are non smokers is 0.48.