What is an equation of the line that is parallel to y=5x−7 and passes through (1, 11) ?

ANSWER[tex]y = 5x + 6[/tex]EXPLANATIONThe given equation is [tex]y = 5x - 7[/tex]The slope of this line is [tex]m = 5[/tex]Any line parallel to this line also has the same slope.If the parallel line passes through (1,11),then, it's equation is given by:[tex]y-y_1=m(x-x_1)[/tex]Substitute the slope and point to get,[tex]y - 11 = 5(x - 1)[/tex][tex]y = 5x - 5 + 11[/tex][tex]y = 5 x + 6[/tex]is the required equation.